Base | Representation |
---|---|
bin | 10111010100001111011001… |
… | …11111100001000101110011 |
3 | 20201112122120120112110021011 |
4 | 23222013230333201011303 |
5 | 23210024101133422224 |
6 | 301014254044011351 |
7 | 13541231516624254 |
oct | 1352075477410563 |
9 | 221478516473234 |
10 | 51273000685939 |
11 | 15378837225a8a |
12 | 5901074230b57 |
13 | 227c03c019b26 |
14 | c938ab08cb2b |
15 | 5ddadd5d8394 |
hex | 2ea1ecfe1173 |
51273000685939 has 4 divisors (see below), whose sum is σ = 51279608890720. Its totient is φ = 51266392481160.
The previous prime is 51273000685867. The next prime is 51273000685979. The reversal of 51273000685939 is 93958600037215.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 51273000685939 - 29 = 51273000685427 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (51273000685979) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3304090752 + ... + 3304106269.
It is an arithmetic number, because the mean of its divisors is an integer number (12819902222680).
Almost surely, 251273000685939 is an apocalyptic number.
51273000685939 is a deficient number, since it is larger than the sum of its proper divisors (6608204781).
51273000685939 is an equidigital number, since it uses as much as digits as its factorization.
51273000685939 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6608204780.
The product of its (nonzero) digits is 12247200, while the sum is 58.
The spelling of 51273000685939 in words is "fifty-one trillion, two hundred seventy-three billion, six hundred eighty-five thousand, nine hundred thirty-nine".
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