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5128143731 = 6253382007
BaseRepresentation
bin1001100011010100…
…10100001101110011
3111020101111200201022
410301222110031303
541000301044411
62204505530055
7241036334234
oct46152241563
914211450638
105128143731
1121a1781317
12bb14a392b
13639577499
143690db08b
15200319edb
hex131a94373

5128143731 has 4 divisors (see below), whose sum is σ = 5128288272. Its totient is φ = 5127999192.

The previous prime is 5128143679. The next prime is 5128143763. The reversal of 5128143731 is 1373418215.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 5128143731 - 230 = 4054401907 is a prime.

It is a super-2 number, since 2×51281437312 = 52595716251589200722, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 5128143691 and 5128143700.

It is not an unprimeable number, because it can be changed into a prime (5128143781) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21530 + ... + 103536.

It is an arithmetic number, because the mean of its divisors is an integer number (1282072068).

Almost surely, 25128143731 is an apocalyptic number.

5128143731 is a deficient number, since it is larger than the sum of its proper divisors (144541).

5128143731 is an equidigital number, since it uses as much as digits as its factorization.

5128143731 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 144540.

The product of its digits is 20160, while the sum is 35.

The square root of 5128143731 is about 71611.0587200050. The cubic root of 5128143731 is about 1724.4610771564.

The spelling of 5128143731 in words is "five billion, one hundred twenty-eight million, one hundred forty-three thousand, seven hundred thirty-one".

Divisors: 1 62533 82007 5128143731