5130034113 has 4 divisors (see below), whose sum is σ = 6840045488. Its totient is φ = 3420022740.

The previous prime is 5130034111. The next prime is 5130034177. The reversal of 5130034113 is 3114300315.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 5130034113 - 2¹ = 5130034111 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 5130034113.

It is not an unprimeable number, because it can be changed into a prime (5130034111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 855005683 + ... + 855005688.

It is an arithmetic number, because the mean of its divisors is an integer number (1710011372).

Almost surely, 2^5130034113 is an apocalyptic number.

It is an amenable number.

5130034113 is a deficient number, since it is larger than the sum of its proper divisors (1710011375).

5130034113 is a wasteful number, since it uses less digits than its factorization.

5130034113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1710011374.

The product of its (nonzero) digits is 540, while the sum is 21.

The square root of 5130034113 is about 71624.2564568736. The cubic root of 5130034113 is about 1724.6729465234.

Adding to 5130034113 its reverse (3114300315), we get a palindrome (8244334428).

The spelling of 5130034113 in words is "five billion, one hundred thirty million, thirty-four thousand, one hundred thirteen".