Base | Representation |
---|---|
bin | 1110111011100011111… |
… | …11010010000001100011 |
3 | 1211001011210110011010111 |
4 | 13131301333102001203 |
5 | 31401122430210111 |
6 | 1031401500112151 |
7 | 52030644664306 |
oct | 7356177220143 |
9 | 1731153404114 |
10 | 513013522531 |
11 | 1886278395a4 |
12 | 83513235657 |
13 | 394b9275773 |
14 | 1ab896acb3d |
15 | d528356a21 |
hex | 7771fd2063 |
513013522531 has 4 divisors (see below), whose sum is σ = 514136090872. Its totient is φ = 511890954192.
The previous prime is 513013522523. The next prime is 513013522537. The reversal of 513013522531 is 135225310315.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 513013522531 - 23 = 513013522523 is a prime.
It is a super-2 number, since 2×5130135225312 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 513013522493 and 513013522502.
It is not an unprimeable number, because it can be changed into a prime (513013522537) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 561283485 + ... + 561284398.
It is an arithmetic number, because the mean of its divisors is an integer number (128534022718).
Almost surely, 2513013522531 is an apocalyptic number.
513013522531 is a deficient number, since it is larger than the sum of its proper divisors (1122568341).
513013522531 is a wasteful number, since it uses less digits than its factorization.
513013522531 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1122568340.
The product of its (nonzero) digits is 13500, while the sum is 31.
Adding to 513013522531 its reverse (135225310315), we get a palindrome (648238832846).
The spelling of 513013522531 in words is "five hundred thirteen billion, thirteen million, five hundred twenty-two thousand, five hundred thirty-one".
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