Base | Representation |
---|---|
bin | 101111110001111101… |
… | …110001010010110011 |
3 | 11220102110210110010112 |
4 | 233301331301102303 |
5 | 1320032330021003 |
6 | 35322505451535 |
7 | 3464236004012 |
oct | 576175612263 |
9 | 156373713115 |
10 | 51304142003 |
11 | 1a83793a264 |
12 | 9b397a0bab |
13 | 4ab7cc809a |
14 | 26a9a0ca79 |
15 | 15041023d8 |
hex | bf1f714b3 |
51304142003 has 4 divisors (see below), whose sum is σ = 51304716000. Its totient is φ = 51303568008.
The previous prime is 51304141969. The next prime is 51304142023. The reversal of 51304142003 is 30024140315.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is not a de Polignac number, because 51304142003 - 26 = 51304141939 is a prime.
It is a super-2 number, since 2×513041420032 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 51304142003.
It is not an unprimeable number, because it can be changed into a prime (51304142023) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 120875 + ... + 342372.
It is an arithmetic number, because the mean of its divisors is an integer number (12826179000).
Almost surely, 251304142003 is an apocalyptic number.
51304142003 is a deficient number, since it is larger than the sum of its proper divisors (573997).
51304142003 is a wasteful number, since it uses less digits than its factorization.
51304142003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 573996.
The product of its (nonzero) digits is 1440, while the sum is 23.
Adding to 51304142003 its reverse (30024140315), we get a palindrome (81328282318).
The spelling of 51304142003 in words is "fifty-one billion, three hundred four million, one hundred forty-two thousand, three".
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