Base | Representation |
---|---|
bin | 1110111011101000010… |
… | …10011110000110111001 |
3 | 1211001021100002220120202 |
4 | 13131310022132012321 |
5 | 31401211300310131 |
6 | 1031405242131545 |
7 | 52031600063012 |
oct | 7356412360671 |
9 | 1731240086522 |
10 | 513050010041 |
11 | 1886463a0168 |
12 | 835234b0bb5 |
13 | 394c39ac5ca |
14 | 1ab9048a009 |
15 | d52b662bcb |
hex | 777429e1b9 |
513050010041 has 4 divisors (see below), whose sum is σ = 513058492800. Its totient is φ = 513041527284.
The previous prime is 513050010007. The next prime is 513050010101. The reversal of 513050010041 is 140010050315.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 513050010041 - 214 = 513049993657 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 513050009995 and 513050010022.
It is not an unprimeable number, because it can be changed into a prime (513050310041) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4150001 + ... + 4271838.
It is an arithmetic number, because the mean of its divisors is an integer number (128264623200).
Almost surely, 2513050010041 is an apocalyptic number.
It is an amenable number.
513050010041 is a deficient number, since it is larger than the sum of its proper divisors (8482759).
513050010041 is an equidigital number, since it uses as much as digits as its factorization.
513050010041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8482758.
The product of its (nonzero) digits is 300, while the sum is 20.
Adding to 513050010041 its reverse (140010050315), we get a palindrome (653060060356).
The spelling of 513050010041 in words is "five hundred thirteen billion, fifty million, ten thousand, forty-one".
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