Base | Representation |
---|---|
bin | 10111010101010110001110… |
… | …11011101110101101010011 |
3 | 20201200021201120110121111020 |
4 | 23222223013123232231103 |
5 | 23211134434431100303 |
6 | 301043543134250523 |
7 | 13544046016254042 |
oct | 1352530733565523 |
9 | 221607646417436 |
10 | 51311025253203 |
11 | 1539297a097191 |
12 | 5908506656a43 |
13 | 22827bba47281 |
14 | c95677158559 |
15 | 5deab6961a53 |
hex | 2eaac76eeb53 |
51311025253203 has 8 divisors (see below), whose sum is σ = 69435815268288. Its totient is φ = 33696792703464.
The previous prime is 51311025253129. The next prime is 51311025253207. The reversal of 51311025253203 is 30235252011315.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 51311025253203 - 214 = 51311025236819 is a prime.
It is not an unprimeable number, because it can be changed into a prime (51311025253207) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 127639366101 + ... + 127639366502.
It is an arithmetic number, because the mean of its divisors is an integer number (8679476908536).
Almost surely, 251311025253203 is an apocalyptic number.
51311025253203 is a deficient number, since it is larger than the sum of its proper divisors (18124790015085).
51311025253203 is a wasteful number, since it uses less digits than its factorization.
51311025253203 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 255278732673.
The product of its (nonzero) digits is 27000, while the sum is 33.
Adding to 51311025253203 its reverse (30235252011315), we get a palindrome (81546277264518).
The spelling of 51311025253203 in words is "fifty-one trillion, three hundred eleven billion, twenty-five million, two hundred fifty-three thousand, two hundred three".
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