Base | Representation |
---|---|
bin | 101111110010011101… |
… | …010110100100100001 |
3 | 11220110001101001222201 |
4 | 233302131112210201 |
5 | 1320041434434103 |
6 | 35323403133201 |
7 | 3464366245330 |
oct | 576235264441 |
9 | 156401331881 |
10 | 51312421153 |
11 | 1a841584534 |
12 | 9b40514201 |
13 | 4ab99365a6 |
14 | 26aab65d17 |
15 | 1504bda51d |
hex | bf2756921 |
51312421153 has 4 divisors (see below), whose sum is σ = 58642767040. Its totient is φ = 43982075268.
The previous prime is 51312421123. The next prime is 51312421177. The reversal of 51312421153 is 35112421315.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-51312421153 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (51312421123) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3665172933 + ... + 3665172946.
It is an arithmetic number, because the mean of its divisors is an integer number (14660691760).
Almost surely, 251312421153 is an apocalyptic number.
It is an amenable number.
51312421153 is a deficient number, since it is larger than the sum of its proper divisors (7330345887).
51312421153 is an equidigital number, since it uses as much as digits as its factorization.
51312421153 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7330345886.
The product of its digits is 3600, while the sum is 28.
Adding to 51312421153 its reverse (35112421315), we get a palindrome (86424842468).
The spelling of 51312421153 in words is "fifty-one billion, three hundred twelve million, four hundred twenty-one thousand, one hundred fifty-three".
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