Base | Representation |
---|---|
bin | 101111110010011111… |
… | …110110011111001011 |
3 | 11220110002121100111122 |
4 | 233302133312133023 |
5 | 1320042121414141 |
6 | 35323425145455 |
7 | 3464404644110 |
oct | 576237663713 |
9 | 156402540448 |
10 | 51313076171 |
11 | 1a841991675 |
12 | 9b4078b28b |
13 | 4ab9b05786 |
14 | 26aac96907 |
15 | 1504cb964b |
hex | bf27f67cb |
51313076171 has 4 divisors (see below), whose sum is σ = 58643515632. Its totient is φ = 43982636712.
The previous prime is 51313076149. The next prime is 51313076201. The reversal of 51313076171 is 17167031315.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 51313076171 - 230 = 50239334347 is a prime.
It is a super-2 number, since 2×513130761712 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (51313076071) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3665219720 + ... + 3665219733.
It is an arithmetic number, because the mean of its divisors is an integer number (14660878908).
Almost surely, 251313076171 is an apocalyptic number.
51313076171 is a deficient number, since it is larger than the sum of its proper divisors (7330439461).
51313076171 is an equidigital number, since it uses as much as digits as its factorization.
51313076171 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7330439460.
The product of its (nonzero) digits is 13230, while the sum is 35.
The spelling of 51313076171 in words is "fifty-one billion, three hundred thirteen million, seventy-six thousand, one hundred seventy-one".
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