Base | Representation |
---|---|
bin | 111010010110011001101001… |
… | …0000000001000011111000001 |
3 | 2111022021102102101011100220022 |
4 | 1310230303102000020133001 |
5 | 1014233110312432401423 |
6 | 5015332433332223225 |
7 | 213052145610054653 |
oct | 16454632200103701 |
9 | 2438242371140808 |
10 | 513252115122113 |
11 | 1395a0aaa593314 |
12 | 49693846a6ab15 |
13 | 1905060b691c23 |
14 | 90a576bb586d3 |
15 | 3e50cea901dc8 |
hex | 1d2ccd20087c1 |
513252115122113 has 16 divisors (see below), whose sum is σ = 519168588217344. Its totient is φ = 507356421433680.
The previous prime is 513252115122037. The next prime is 513252115122199. The reversal of 513252115122113 is 311221511252315.
It is a cyclic number.
It is not a de Polignac number, because 513252115122113 - 210 = 513252115121089 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (513252115124113) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4228865756 + ... + 4228987122.
It is an arithmetic number, because the mean of its divisors is an integer number (32448036763584).
Almost surely, 2513252115122113 is an apocalyptic number.
It is an amenable number.
513252115122113 is a deficient number, since it is larger than the sum of its proper divisors (5916473095231).
513252115122113 is a wasteful number, since it uses less digits than its factorization.
513252115122113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 206572.
The product of its digits is 18000, while the sum is 35.
Adding to 513252115122113 its reverse (311221511252315), we get a palindrome (824473626374428).
The spelling of 513252115122113 in words is "five hundred thirteen trillion, two hundred fifty-two billion, one hundred fifteen million, one hundred twenty-two thousand, one hundred thirteen".
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