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513342343243315 = 5102668468648663
BaseRepresentation
bin111010010111000011101010…
…0000001000110011000110011
32111022121001022112021211111001
41310232013110001012120303
51014241100104332241230
65015442114502102431
7213061521546330625
oct16456072401063063
92438531275254431
10513342343243315
111396262a0a54223
12496a922811aa17
1319058c8a836261
1490a9c8b078c15
153e5332bce00ca
hex1d2e1d4046633

513342343243315 has 4 divisors (see below), whose sum is σ = 616010811891984. Its totient is φ = 410673874594648.

The previous prime is 513342343243313. The next prime is 513342343243339.

513342343243315 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 513342343243315 - 21 = 513342343243313 is a prime.

It is a super-2 number, since 2×5133423432433152 (a number of 30 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (513342343243313) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 51334234324327 + ... + 51334234324336.

It is an arithmetic number, because the mean of its divisors is an integer number (154002702972996).

Almost surely, 2513342343243315 is an apocalyptic number.

513342343243315 is a deficient number, since it is larger than the sum of its proper divisors (102668468648669).

513342343243315 is a wasteful number, since it uses less digits than its factorization.

513342343243315 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 102668468648668.

The product of its digits is 4665600, while the sum is 46.

The spelling of 513342343243315 in words is "five hundred thirteen trillion, three hundred forty-two billion, three hundred forty-three million, two hundred forty-three thousand, three hundred fifteen".

Divisors: 1 5 102668468648663 513342343243315