Base | Representation |
---|---|
bin | 10111010110000011001011… |
… | …01100010100111010011011 |
3 | 20201202121000020021222101021 |
4 | 23223001211230110322123 |
5 | 23212033344220144403 |
6 | 301103013355503311 |
7 | 13545562000623403 |
oct | 1353014554247233 |
9 | 221677006258337 |
10 | 51335155240603 |
11 | 153a2131912933 |
12 | 591111b757b37 |
13 | 2284b65c56420 |
14 | c968c5b4d803 |
15 | 5e052a07c8bd |
hex | 2eb065b14e9b |
51335155240603 has 4 divisors (see below), whose sum is σ = 55284013336048. Its totient is φ = 47386297145160.
The previous prime is 51335155240559. The next prime is 51335155240679. The reversal of 51335155240603 is 30604255153315.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-51335155240603 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 51335155240603.
It is not an unprimeable number, because it can be changed into a prime (51335155280603) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1974429047703 + ... + 1974429047728.
It is an arithmetic number, because the mean of its divisors is an integer number (13821003334012).
Almost surely, 251335155240603 is an apocalyptic number.
51335155240603 is a deficient number, since it is larger than the sum of its proper divisors (3948858095445).
51335155240603 is a wasteful number, since it uses less digits than its factorization.
51335155240603 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3948858095444.
The product of its (nonzero) digits is 810000, while the sum is 43.
The spelling of 51335155240603 in words is "fifty-one trillion, three hundred thirty-five billion, one hundred fifty-five million, two hundred forty thousand, six hundred three".
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