Base | Representation |
---|---|
bin | 100101010110011111101… |
… | …1100110111110101000011 |
3 | 200011202120221212000121112 |
4 | 1022230333130313311003 |
5 | 1133102002403431120 |
6 | 14530153122113535 |
7 | 1036613110605455 |
oct | 112547734676503 |
9 | 20152527760545 |
10 | 5133550452035 |
11 | 16aa143442875 |
12 | 6aaabb7ab8ab |
13 | 2b31266bb495 |
14 | 13a6725c42d5 |
15 | 8d80710abc5 |
hex | 4ab3f737d43 |
5133550452035 has 4 divisors (see below), whose sum is σ = 6160260542448. Its totient is φ = 4106840361624.
The previous prime is 5133550452031. The next prime is 5133550452047. The reversal of 5133550452035 is 5302540553315.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5133550452035 - 22 = 5133550452031 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 5133550451983 and 5133550452001.
It is not an unprimeable number, because it can be changed into a prime (5133550452031) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 513355045199 + ... + 513355045208.
It is an arithmetic number, because the mean of its divisors is an integer number (1540065135612).
Almost surely, 25133550452035 is an apocalyptic number.
5133550452035 is a deficient number, since it is larger than the sum of its proper divisors (1026710090413).
5133550452035 is a wasteful number, since it uses less digits than its factorization.
5133550452035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1026710090412.
The product of its (nonzero) digits is 675000, while the sum is 41.
The spelling of 5133550452035 in words is "five trillion, one hundred thirty-three billion, five hundred fifty million, four hundred fifty-two thousand, thirty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •