Search a number
-
+
51340133353 = 2318711193041
BaseRepresentation
bin101111110100000111…
…000100001111101001
311220111222111222222111
4233310013010033221
51320121033231403
635330233122321
73465153635035
oct576407041751
9156458458874
1051340133353
111a856192083
129b498593a1
134ac25ba142
1426b06db1c5
15150736156d
hexbf41c43e9

51340133353 has 8 divisors (see below), whose sum is σ = 53600990976. Its totient is φ = 49081665600.

The previous prime is 51340133347. The next prime is 51340133437. The reversal of 51340133353 is 35333104315.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 51340133353 - 217 = 51340002281 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (51340133153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 553488 + ... + 639553.

It is an arithmetic number, because the mean of its divisors is an integer number (6700123872).

Almost surely, 251340133353 is an apocalyptic number.

It is an amenable number.

51340133353 is a deficient number, since it is larger than the sum of its proper divisors (2260857623).

51340133353 is a wasteful number, since it uses less digits than its factorization.

51340133353 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1194935.

The product of its (nonzero) digits is 24300, while the sum is 31.

Adding to 51340133353 its reverse (35333104315), we get a palindrome (86673237668).

The spelling of 51340133353 in words is "fifty-one billion, three hundred forty million, one hundred thirty-three thousand, three hundred fifty-three".

Divisors: 1 23 1871 43033 1193041 27439943 2232179711 51340133353