Base | Representation |
---|---|
bin | 111010010111101000011111… |
… | …1010110000110010011101011 |
3 | 2111022212121111211212012011222 |
4 | 1310233100333112012103223 |
5 | 1014243344114022241301 |
6 | 5015542320505412255 |
7 | 213100322144030063 |
oct | 16457207726062353 |
9 | 2438777454765158 |
10 | 513421453321451 |
11 | 1396568a7591894 |
12 | 49700625a9a08b |
13 | 1906358749298c |
14 | 90ada3395c3a3 |
15 | 3e5540c0c331b |
hex | 1d2f43f5864eb |
513421453321451 has 4 divisors (see below), whose sum is σ = 514901054051832. Its totient is φ = 511941852591072.
The previous prime is 513421453321433. The next prime is 513421453321519. The reversal of 513421453321451 is 154123354124315.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 513421453321451 - 210 = 513421453320427 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (513421453321151) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 739800364670 + ... + 739800365363.
It is an arithmetic number, because the mean of its divisors is an integer number (128725263512958).
Almost surely, 2513421453321451 is an apocalyptic number.
513421453321451 is a deficient number, since it is larger than the sum of its proper divisors (1479600730381).
513421453321451 is a wasteful number, since it uses less digits than its factorization.
513421453321451 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1479600730380.
The product of its digits is 864000, while the sum is 44.
The spelling of 513421453321451 in words is "five hundred thirteen trillion, four hundred twenty-one billion, four hundred fifty-three million, three hundred twenty-one thousand, four hundred fifty-one".
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