Base | Representation |
---|---|
bin | 111010010111101001110111… |
… | …1110000011011010010001011 |
3 | 2111022212220011010001002220100 |
4 | 1310233103233300123102023 |
5 | 1014243421144212410011 |
6 | 5015543530314100443 |
7 | 213100455403011564 |
oct | 16457235760332213 |
9 | 2438786133032810 |
10 | 513424413013131 |
11 | 139658086220a74 |
12 | 4970111111a723 |
13 | 19063939703229 |
14 | 90adc34a7116b |
15 | 3e55531d53d56 |
hex | 1d2f4efc1b48b |
513424413013131 has 6 divisors (see below), whose sum is σ = 741613041018980. Its totient is φ = 342282942008748.
The previous prime is 513424413013079. The next prime is 513424413013229. The reversal of 513424413013131 is 131310314424315.
513424413013131 is a `hidden beast` number, since 5 + 1 + 3 + 42 + 441 + 30 + 13 + 131 = 666.
It is not a de Polignac number, because 513424413013131 - 219 = 513424412488843 is a prime.
It is a super-2 number, since 2×5134244130131312 (a number of 30 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (513424413014131) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 28523578500721 + ... + 28523578500738.
Almost surely, 2513424413013131 is an apocalyptic number.
513424413013131 is a deficient number, since it is larger than the sum of its proper divisors (228188628005849).
513424413013131 is a wasteful number, since it uses less digits than its factorization.
513424413013131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 57047157001465 (or 57047157001462 counting only the distinct ones).
The product of its (nonzero) digits is 51840, while the sum is 36.
Adding to 513424413013131 its reverse (131310314424315), we get a palindrome (644734727437446).
The spelling of 513424413013131 in words is "five hundred thirteen trillion, four hundred twenty-four billion, four hundred thirteen million, thirteen thousand, one hundred thirty-one".
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