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51343401 = 317114467
BaseRepresentation
bin1100001111011…
…1000000101001
310120121111220110
43003313000221
5101120442101
65032244533
71162261134
oct303670051
9116544813
1051343401
1126a8906a
1215240749
13a838a15
146b6721b
154792cd6
hex30f7029

51343401 has 4 divisors (see below), whose sum is σ = 68457872. Its totient is φ = 34228932.

The previous prime is 51343399. The next prime is 51343423. The reversal of 51343401 is 10434315.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 51343401 - 21 = 51343399 is a prime.

It is a super-2 number, since 2×513434012 = 5272289652493602, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (51343441) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8557231 + ... + 8557236.

It is an arithmetic number, because the mean of its divisors is an integer number (17114468).

Almost surely, 251343401 is an apocalyptic number.

It is an amenable number.

51343401 is a deficient number, since it is larger than the sum of its proper divisors (17114471).

51343401 is a wasteful number, since it uses less digits than its factorization.

51343401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17114470.

The product of its (nonzero) digits is 720, while the sum is 21.

The square root of 51343401 is about 7165.4309709884. The cubic root of 51343401 is about 371.6734546230.

Adding to 51343401 its reverse (10434315), we get a palindrome (61777716).

The spelling of 51343401 in words is "fifty-one million, three hundred forty-three thousand, four hundred one".

Divisors: 1 3 17114467 51343401