51345134747 has 4 divisors (see below), whose sum is σ = 54047510280. Its totient is φ = 48642759216.

The previous prime is 51345134741. The next prime is 51345134761. The reversal of 51345134747 is 74743154315.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-51345134747 is a prime.

It is a super-3 number, since 3×51345134747³ (a number of 33 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 51345134698 and 51345134707.

It is not an unprimeable number, because it can be changed into a prime (51345134741) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1351187738 + ... + 1351187775.

It is an arithmetic number, because the mean of its divisors is an integer number (13511877570).

Almost surely, 2^51345134747 is an apocalyptic number.

51345134747 is a deficient number, since it is larger than the sum of its proper divisors (2702375533).

51345134747 is a wasteful number, since it uses less digits than its factorization.

51345134747 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2702375532.

The product of its digits is 705600, while the sum is 44.

The spelling of 51345134747 in words is "fifty-one billion, three hundred forty-five million, one hundred thirty-four thousand, seven hundred forty-seven".