Base | Representation |
---|---|
bin | 111010010111110111110011… |
… | …1101111001011111010000001 |
3 | 2111022222202102000001020101020 |
4 | 1310233233213233023322001 |
5 | 1014244413443332210340 |
6 | 5020005400254500053 |
7 | 213102565164524262 |
oct | 16457574757137201 |
9 | 2438882360036336 |
10 | 513454343241345 |
11 | 13966984503a470 |
12 | 49706a84804629 |
13 | 190666c94a963c |
14 | 90b1473b16969 |
15 | 3e561d47999d0 |
hex | 1d2fbe7bcbe81 |
513454343241345 has 16 divisors (see below), whose sum is σ = 896211217294272. Its totient is φ = 248947560359360.
The previous prime is 513454343241341. The next prime is 513454343241487. The reversal of 513454343241345 is 543142343454315.
It is not a de Polignac number, because 513454343241345 - 22 = 513454343241341 is a prime.
It is not an unprimeable number, because it can be changed into a prime (513454343241341) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1555922252082 + ... + 1555922252411.
It is an arithmetic number, because the mean of its divisors is an integer number (56013201080892).
Almost surely, 2513454343241345 is an apocalyptic number.
513454343241345 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
It is an amenable number.
513454343241345 is a deficient number, since it is larger than the sum of its proper divisors (382756874052927).
513454343241345 is a wasteful number, since it uses less digits than its factorization.
513454343241345 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3111844504512.
The product of its digits is 20736000, while the sum is 51.
The spelling of 513454343241345 in words is "five hundred thirteen trillion, four hundred fifty-four billion, three hundred forty-three million, two hundred forty-one thousand, three hundred forty-five".
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