Base | Representation |
---|---|
bin | 111010010111110111110101… |
… | …1001000101000011101100011 |
3 | 2111022222202112222022020201012 |
4 | 1310233233223020220131203 |
5 | 1014244414102430243210 |
6 | 5020005410052331135 |
7 | 213102566456164421 |
oct | 16457575310503543 |
9 | 2438882488266635 |
10 | 513454400243555 |
11 | 139669874233031 |
12 | 49706a9b913aab |
13 | 19066708246c64 |
14 | 90b147b514111 |
15 | 3e561d97a9305 |
hex | 1d2fbeb228763 |
513454400243555 has 8 divisors (see below), whose sum is σ = 618789680638272. Its totient is φ = 409000586630848.
The previous prime is 513454400243549. The next prime is 513454400243639. The reversal of 513454400243555 is 555342004454315.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 513454400243555 - 28 = 513454400243299 is a prime.
It is a super-2 number, since 2×5134544002435552 (a number of 30 digits) contains 22 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 220366694219 + ... + 220366696548.
It is an arithmetic number, because the mean of its divisors is an integer number (77348710079784).
Almost surely, 2513454400243555 is an apocalyptic number.
513454400243555 is a deficient number, since it is larger than the sum of its proper divisors (105335280394717).
513454400243555 is a wasteful number, since it uses less digits than its factorization.
513454400243555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 440733391005.
The product of its (nonzero) digits is 14400000, while the sum is 50.
The spelling of 513454400243555 in words is "five hundred thirteen trillion, four hundred fifty-four billion, four hundred million, two hundred forty-three thousand, five hundred fifty-five".
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