Base | Representation |
---|---|
bin | 100101010111001111100… |
… | …0010101100100110110001 |
3 | 200011220201201121000102112 |
4 | 1022232133002230212301 |
5 | 1133113243433444212 |
6 | 14531020212055105 |
7 | 1040000623350434 |
oct | 112563702544661 |
9 | 20156651530375 |
10 | 5135154203057 |
11 | 16aa89674673a |
12 | 6ab288904495 |
13 | 2b3320a38698 |
14 | 13a7855b381b |
15 | 8d89cceb422 |
hex | 4ab9f0ac9b1 |
5135154203057 has 4 divisors (see below), whose sum is σ = 5147013682020. Its totient is φ = 5123294724096.
The previous prime is 5135154202999. The next prime is 5135154203161. The reversal of 5135154203057 is 7503024515315.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 2331374749456 + 2803779453601 = 1526884^2 + 1674449^2 .
It is a cyclic number.
It is not a de Polignac number, because 5135154203057 - 26 = 5135154202993 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5135153203057) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5929738832 + ... + 5929739697.
It is an arithmetic number, because the mean of its divisors is an integer number (1286753420505).
Almost surely, 25135154203057 is an apocalyptic number.
It is an amenable number.
5135154203057 is a deficient number, since it is larger than the sum of its proper divisors (11859478963).
5135154203057 is a wasteful number, since it uses less digits than its factorization.
5135154203057 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11859478962.
The product of its (nonzero) digits is 315000, while the sum is 41.
The spelling of 5135154203057 in words is "five trillion, one hundred thirty-five billion, one hundred fifty-four million, two hundred three thousand, fifty-seven".
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