Base | Representation |
---|---|
bin | 10111010110100100111101… |
… | …00111011110000000000001 |
3 | 20201211022211002022012022001 |
4 | 23223102132213132000001 |
5 | 23212333014233400401 |
6 | 301115213101344001 |
7 | 13550103254663254 |
oct | 1353223647360001 |
9 | 221738732265261 |
10 | 51353290137601 |
11 | 153a9898561411 |
12 | 5914740b68001 |
13 | 22867960c83ca |
14 | c9772645309b |
15 | 5e0c3c1d0601 |
hex | 2eb49e9de001 |
51353290137601 has 4 divisors (see below), whose sum is σ = 51353304487600. Its totient is φ = 51353275787604.
The previous prime is 51353290137557. The next prime is 51353290137607. The reversal of 51353290137601 is 10673109235315.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is not a de Polignac number, because 51353290137601 - 215 = 51353290104833 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (51353290137607) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3052270 + ... + 10584088.
It is an arithmetic number, because the mean of its divisors is an integer number (12838326121900).
Almost surely, 251353290137601 is an apocalyptic number.
It is an amenable number.
51353290137601 is a deficient number, since it is larger than the sum of its proper divisors (14349999).
51353290137601 is an equidigital number, since it uses as much as digits as its factorization.
51353290137601 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14349998.
The product of its (nonzero) digits is 510300, while the sum is 46.
The spelling of 51353290137601 in words is "fifty-one trillion, three hundred fifty-three billion, two hundred ninety million, one hundred thirty-seven thousand, six hundred one".
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