Base | Representation |
---|---|
bin | 100101010111010111011… |
… | …1000101010111111010011 |
3 | 200011221102020202102121211 |
4 | 1022232232320222333103 |
5 | 1133114320010313301 |
6 | 14531102425200551 |
7 | 1040010331600213 |
oct | 112565670527723 |
9 | 20157366672554 |
10 | 5135420010451 |
11 | 16aaa12796775 |
12 | 6ab341930157 |
13 | 2b3363b24073 |
14 | 13a7aca06243 |
15 | 8d8b6304051 |
hex | 4abaee2afd3 |
5135420010451 has 4 divisors (see below), whose sum is σ = 5135657113504. Its totient is φ = 5135182907400.
The previous prime is 5135420010421. The next prime is 5135420010517. The reversal of 5135420010451 is 1540100245315.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5135420010451 - 219 = 5135419486163 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5135420010421) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 118519035 + ... + 118562356.
It is an arithmetic number, because the mean of its divisors is an integer number (1283914278376).
Almost surely, 25135420010451 is an apocalyptic number.
5135420010451 is a deficient number, since it is larger than the sum of its proper divisors (237103053).
5135420010451 is a wasteful number, since it uses less digits than its factorization.
5135420010451 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 237103052.
The product of its (nonzero) digits is 12000, while the sum is 31.
Adding to 5135420010451 its reverse (1540100245315), we get a palindrome (6675520255766).
The spelling of 5135420010451 in words is "five trillion, one hundred thirty-five billion, four hundred twenty million, ten thousand, four hundred fifty-one".
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