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5136921394513 = 8361890619211
BaseRepresentation
bin100101011000000100001…
…0111111111110101010001
3200012002021212212122100221
41022300020113333311101
51133130403334111023
614531511421113041
71040062462261216
oct112601027776521
920162255778327
105136921394513
111700613231847
126ab6a06b8781
132b3542bac2bc
1413a8b2189b0d
158d95302385d
hex4ac085ffd51

5136921394513 has 4 divisors (see below), whose sum is σ = 5198812013808. Its totient is φ = 5075030775220.

The previous prime is 5136921394457. The next prime is 5136921394523. The reversal of 5136921394513 is 3154931296315.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5136921394513 - 213 = 5136921386321 is a prime.

It is a super-2 number, since 2×51369213945132 (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5136921394523) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 30945309523 + ... + 30945309688.

It is an arithmetic number, because the mean of its divisors is an integer number (1299703003452).

Almost surely, 25136921394513 is an apocalyptic number.

It is an amenable number.

5136921394513 is a deficient number, since it is larger than the sum of its proper divisors (61890619295).

5136921394513 is an equidigital number, since it uses as much as digits as its factorization.

5136921394513 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 61890619294.

The product of its digits is 2624400, while the sum is 52.

The spelling of 5136921394513 in words is "five trillion, one hundred thirty-six billion, nine hundred twenty-one million, three hundred ninety-four thousand, five hundred thirteen".

Divisors: 1 83 61890619211 5136921394513