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514026113 = 598712307
BaseRepresentation
bin11110101000110…
…110101010000001
31022211020020021012
4132220312222001
52023042313423
6123001210305
715511102256
oct3650665201
91284206235
10514026113
11244177477
12124190995
1382656383
144c3a742d
15301d9078
hex1ea36a81

514026113 has 4 divisors (see below), whose sum is σ = 522738480. Its totient is φ = 505313748.

The previous prime is 514026083. The next prime is 514026137. The reversal of 514026113 is 311620415.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311620415 = 562324083.

It is a cyclic number.

It is not a de Polignac number, because 514026113 - 28 = 514025857 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (514026313) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4356095 + ... + 4356212.

It is an arithmetic number, because the mean of its divisors is an integer number (130684620).

Almost surely, 2514026113 is an apocalyptic number.

It is an amenable number.

514026113 is a deficient number, since it is larger than the sum of its proper divisors (8712367).

514026113 is an equidigital number, since it uses as much as digits as its factorization.

514026113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8712366.

The product of its (nonzero) digits is 720, while the sum is 23.

The square root of 514026113 is about 22672.1439877220. The cubic root of 514026113 is about 801.0538782536.

Adding to 514026113 its reverse (311620415), we get a palindrome (825646528).

The spelling of 514026113 in words is "five hundred fourteen million, twenty-six thousand, one hundred thirteen".

Divisors: 1 59 8712307 514026113