Base | Representation |
---|---|
bin | 100101011001101111110… |
… | …1110010000111001111011 |
3 | 200012102121200020221022101 |
4 | 1022303133232100321323 |
5 | 1133210303242124201 |
6 | 14533310123004231 |
7 | 1040251142611555 |
oct | 112633756207173 |
9 | 20172550227271 |
10 | 5140534333051 |
11 | 17020a7687a67 |
12 | 6b032a669677 |
13 | 2b399a56c660 |
14 | 13ab35d464d5 |
15 | 8dab52ddd01 |
hex | 4acdfb90e7b |
5140534333051 has 4 divisors (see below), whose sum is σ = 5535960050992. Its totient is φ = 4745108615112.
The previous prime is 5140534333049. The next prime is 5140534333097. The reversal of 5140534333051 is 1503334350415.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5140534333051 - 21 = 5140534333049 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 5140534333051.
It is not an unprimeable number, because it can be changed into a prime (5140534333021) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 197712858951 + ... + 197712858976.
It is an arithmetic number, because the mean of its divisors is an integer number (1383990012748).
Almost surely, 25140534333051 is an apocalyptic number.
5140534333051 is a deficient number, since it is larger than the sum of its proper divisors (395425717941).
5140534333051 is a wasteful number, since it uses less digits than its factorization.
5140534333051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 395425717940.
The product of its (nonzero) digits is 162000, while the sum is 37.
Adding to 5140534333051 its reverse (1503334350415), we get a palindrome (6643868683466).
The spelling of 5140534333051 in words is "five trillion, one hundred forty billion, five hundred thirty-four million, three hundred thirty-three thousand, fifty-one".
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