Base | Representation |
---|---|
bin | 111010011100110111100101… |
… | …0111110011001000100011011 |
3 | 2111102102101221011020011201020 |
4 | 1310321233022332121010123 |
5 | 1014342141340144034030 |
6 | 5021253050140453523 |
7 | 213203315435164365 |
oct | 16471571276310433 |
9 | 2442371834204636 |
10 | 514141055455515 |
11 | 139903aa71a1984 |
12 | 497b7b9324a2a3 |
13 | 190b63a7a623c7 |
14 | 90d67ba37bd35 |
15 | 3e68ec7005510 |
hex | 1d39bcaf9911b |
514141055455515 has 16 divisors (see below), whose sum is σ = 831868673997600. Its totient is φ = 271127567820032.
The previous prime is 514141055455439. The next prime is 514141055455519. The reversal of 514141055455515 is 515554550141415.
It is a cyclic number.
It is not a de Polignac number, because 514141055455515 - 217 = 514141055324443 is a prime.
It is a super-3 number, since 3×5141410554555153 (a number of 45 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (514141055455519) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 192562191720 + ... + 192562194389.
It is an arithmetic number, because the mean of its divisors is an integer number (51991792124850).
Almost surely, 2514141055455515 is an apocalyptic number.
514141055455515 is a deficient number, since it is larger than the sum of its proper divisors (317727618542085).
514141055455515 is a wasteful number, since it uses less digits than its factorization.
514141055455515 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 385124386206.
The product of its (nonzero) digits is 5000000, while the sum is 51.
The spelling of 514141055455515 in words is "five hundred fourteen trillion, one hundred forty-one billion, fifty-five million, four hundred fifty-five thousand, five hundred fifteen".
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