Base | Representation |
---|---|
bin | 10111011000010110011100… |
… | …00101100111100010111001 |
3 | 20202001011002010021101112222 |
4 | 23230023032011213202321 |
5 | 23214332303311043223 |
6 | 301203210444413425 |
7 | 13554361130141555 |
oct | 1354131605474271 |
9 | 222034063241488 |
10 | 51414216112313 |
11 | 154227126a1a2a |
12 | 5924504b47275 |
13 | 228c455644a12 |
14 | c9a665ca4865 |
15 | 5e2605d910c8 |
hex | 2ec2ce1678b9 |
51414216112313 has 4 divisors (see below), whose sum is σ = 51414233505360. Its totient is φ = 51414198719268.
The previous prime is 51414216112309. The next prime is 51414216112321. The reversal of 51414216112313 is 31321161241415.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 51414216112313 - 22 = 51414216112309 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (51414216112813) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3033095 + ... + 10584332.
It is an arithmetic number, because the mean of its divisors is an integer number (12853558376340).
Almost surely, 251414216112313 is an apocalyptic number.
It is an amenable number.
51414216112313 is a deficient number, since it is larger than the sum of its proper divisors (17393047).
51414216112313 is a wasteful number, since it uses less digits than its factorization.
51414216112313 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17393046.
The product of its digits is 17280, while the sum is 35.
Adding to 51414216112313 its reverse (31321161241415), we get a palindrome (82735377353728).
The spelling of 51414216112313 in words is "fifty-one trillion, four hundred fourteen billion, two hundred sixteen million, one hundred twelve thousand, three hundred thirteen".
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