Base | Representation |
---|---|
bin | 1110111101111111001… |
… | …01101101000100110001 |
3 | 1211011112112020102202001 |
4 | 13132333211231010301 |
5 | 31411304223043213 |
6 | 1032135004454001 |
7 | 52105134053314 |
oct | 7367745550461 |
9 | 1734475212661 |
10 | 514315440433 |
11 | 189135726803 |
12 | 8381724a301 |
13 | 39665c026a2 |
14 | 1ac7056c97b |
15 | d5a27c51dd |
hex | 77bf96d131 |
514315440433 has 16 divisors (see below), whose sum is σ = 559230793920. Its totient is φ = 471336947136.
The previous prime is 514315440421. The next prime is 514315440439. The reversal of 514315440433 is 334044513415.
It is not a de Polignac number, because 514315440433 - 233 = 505725505841 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (37).
It is a junction number, because it is equal to n+sod(n) for n = 514315440392 and 514315440401.
It is not an unprimeable number, because it can be changed into a prime (514315440439) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1992835 + ... + 2236072.
It is an arithmetic number, because the mean of its divisors is an integer number (34951924620).
Almost surely, 2514315440433 is an apocalyptic number.
It is an amenable number.
514315440433 is a deficient number, since it is larger than the sum of its proper divisors (44915353487).
514315440433 is a wasteful number, since it uses less digits than its factorization.
514315440433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4229136.
The product of its (nonzero) digits is 172800, while the sum is 37.
Adding to 514315440433 its reverse (334044513415), we get a palindrome (848359953848).
The spelling of 514315440433 in words is "five hundred fourteen billion, three hundred fifteen million, four hundred forty thousand, four hundred thirty-three".
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