Base | Representation |
---|---|
bin | 100101011010111111011… |
… | …0010110110010010110001 |
3 | 200012200111200000221221100 |
4 | 1022311332302312102301 |
5 | 1133231234444041423 |
6 | 14534431020115013 |
7 | 1040404240062543 |
oct | 112657662662261 |
9 | 20180450027840 |
10 | 5143203112113 |
11 | 170324708a1a0 |
12 | 6b0954395a69 |
13 | 2b4004444471 |
14 | 13ad0a56d693 |
15 | 8dbbe758343 |
hex | 4ad7ecb64b1 |
5143203112113 has 12 divisors (see below), whose sum is σ = 8104441267728. Its totient is φ = 3117092795160.
The previous prime is 5143203112049. The next prime is 5143203112147. The reversal of 5143203112113 is 3112113023415.
5143203112113 is a `hidden beast` number, since 5 + 1 + 4 + 320 + 311 + 21 + 1 + 3 = 666.
It is not a de Polignac number, because 5143203112113 - 26 = 5143203112049 is a prime.
It is not an unprimeable number, because it can be changed into a prime (5143203112013) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 25975773195 + ... + 25975773392.
It is an arithmetic number, because the mean of its divisors is an integer number (675370105644).
Almost surely, 25143203112113 is an apocalyptic number.
It is an amenable number.
5143203112113 is a deficient number, since it is larger than the sum of its proper divisors (2961238155615).
5143203112113 is a wasteful number, since it uses less digits than its factorization.
5143203112113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 51951546604 (or 51951546601 counting only the distinct ones).
The product of its (nonzero) digits is 2160, while the sum is 27.
Adding to 5143203112113 its reverse (3112113023415), we get a palindrome (8255316135528).
The spelling of 5143203112113 in words is "five trillion, one hundred forty-three billion, two hundred three million, one hundred twelve thousand, one hundred thirteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.079 sec. • engine limits •