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5143314115 = 51028662823
BaseRepresentation
bin1001100101001000…
…01011111011000011
3111021110001102120101
410302210023323003
541013142022430
62210211023231
7241312306612
oct46244137303
914243042511
105143314115
1121aa2a3025
12bb659ab17
1363c759544
1436b129879
15201814dca
hex13290bec3

5143314115 has 4 divisors (see below), whose sum is σ = 6171976944. Its totient is φ = 4114651288.

The previous prime is 5143314109. The next prime is 5143314217. The reversal of 5143314115 is 5114133415.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5143314115 - 25 = 5143314083 is a prime.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 514331407 + ... + 514331416.

It is an arithmetic number, because the mean of its divisors is an integer number (1542994236).

Almost surely, 25143314115 is an apocalyptic number.

5143314115 is a deficient number, since it is larger than the sum of its proper divisors (1028662829).

5143314115 is a wasteful number, since it uses less digits than its factorization.

5143314115 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1028662828.

The product of its digits is 3600, while the sum is 28.

The square root of 5143314115 is about 71716.9025753344. The cubic root of 5143314115 is about 1726.1598713440.

The spelling of 5143314115 in words is "five billion, one hundred forty-three million, three hundred fourteen thousand, one hundred fifteen".

Divisors: 1 5 1028662823 5143314115