Base | Representation |
---|---|
bin | 1100010000110… |
… | …1001010000001 |
3 | 10120210010100011 |
4 | 3010031022001 |
5 | 101131342423 |
6 | 5034224521 |
7 | 1163116453 |
oct | 304151201 |
9 | 116703304 |
10 | 51434113 |
11 | 27040235 |
12 | 15285141 |
13 | a86b0b3 |
14 | 6b8c2d3 |
15 | 47aeb0d |
hex | 310d281 |
51434113 has 4 divisors (see below), whose sum is σ = 51599808. Its totient is φ = 51268420.
The previous prime is 51434093. The next prime is 51434171. The reversal of 51434113 is 31143415.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31143415 = 5 ⋅6228683.
It is a cyclic number.
It is not a de Polignac number, because 51434113 - 29 = 51433601 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (51432113) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 82381 + ... + 83002.
It is an arithmetic number, because the mean of its divisors is an integer number (12899952).
Almost surely, 251434113 is an apocalyptic number.
It is an amenable number.
51434113 is a deficient number, since it is larger than the sum of its proper divisors (165695).
51434113 is a wasteful number, since it uses less digits than its factorization.
51434113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 165694.
The product of its digits is 720, while the sum is 22.
The square root of 51434113 is about 7171.7580132071. The cubic root of 51434113 is about 371.8922130582.
Adding to 51434113 its reverse (31143415), we get a palindrome (82577528).
The spelling of 51434113 in words is "fifty-one million, four hundred thirty-four thousand, one hundred thirteen".
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