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5143414081 = 131398873209
BaseRepresentation
bin1001100101001001…
…00100010101000001
3111021110020111200211
410302210210111001
541013203222311
62210213114121
7241313204221
oct46244442501
914243214624
105143414081
1121aa361143
12bb6628941
1363c792bb0
1436b154081
15201834821
hex132924541

5143414081 has 16 divisors (see below), whose sum is σ = 5586940800. Its totient is φ = 4706828928.

The previous prime is 5143414049. The next prime is 5143414109. The reversal of 5143414081 is 1804143415.

It is a cyclic number.

It is not a de Polignac number, because 5143414081 - 25 = 5143414049 is a prime.

It is a super-2 number, since 2×51434140812 = 52909416817258149122, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5143418081) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1601205 + ... + 1604413.

It is an arithmetic number, because the mean of its divisors is an integer number (349183800).

Almost surely, 25143414081 is an apocalyptic number.

It is an amenable number.

5143414081 is a deficient number, since it is larger than the sum of its proper divisors (443526719).

5143414081 is a wasteful number, since it uses less digits than its factorization.

5143414081 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4248.

The product of its (nonzero) digits is 7680, while the sum is 31.

The square root of 5143414081 is about 71717.5995206198. The cubic root of 5143414081 is about 1726.1710545472.

Adding to 5143414081 its reverse (1804143415), we get a palindrome (6947557496).

The spelling of 5143414081 in words is "five billion, one hundred forty-three million, four hundred fourteen thousand, eighty-one".

Divisors: 1 13 139 887 1807 3209 11531 41717 123293 446051 1602809 2846383 5798663 37002979 395647237 5143414081