Base | Representation |
---|---|
bin | 10111011000111011101010… |
… | …11010010100001001011011 |
3 | 20202010001200001111202101010 |
4 | 23230131311122110021123 |
5 | 23220144222004432024 |
6 | 301220314033225003 |
7 | 13555666334455512 |
oct | 1354356532241133 |
9 | 222101601452333 |
10 | 51434203202139 |
11 | 1543013990338a |
12 | 5928362702163 |
13 | 22912bc44c2a4 |
14 | c9b600589679 |
15 | 5e2dc590bb29 |
hex | 2ec77569425b |
51434203202139 has 8 divisors (see below), whose sum is σ = 68579142657552. Its totient is φ = 34289366274080.
The previous prime is 51434203202119. The next prime is 51434203202149. The reversal of 51434203202139 is 93120230243415.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 51434203202139 - 212 = 51434203198043 is a prime.
It is a super-2 number, since 2×514342032021392 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 51434203202097 and 51434203202106.
It is not an unprimeable number, because it can be changed into a prime (51434203202119) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 24453552 + ... + 26473469.
It is an arithmetic number, because the mean of its divisors is an integer number (8572392832194).
Almost surely, 251434203202139 is an apocalyptic number.
51434203202139 is a deficient number, since it is larger than the sum of its proper divisors (17144939455413).
51434203202139 is a wasteful number, since it uses less digits than its factorization.
51434203202139 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 51263677.
The product of its (nonzero) digits is 155520, while the sum is 39.
The spelling of 51434203202139 in words is "fifty-one trillion, four hundred thirty-four billion, two hundred three million, two hundred two thousand, one hundred thirty-nine".
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