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51434205211 = 173025541483
BaseRepresentation
bin101111111001101101…
…111011000000011011
311220202112112100022101
4233321231323000123
51320314124031321
635343433304231
73500405350024
oct577155730033
9156675470271
1051434205211
111a8a42a4714
129b75265077
134b08c3656c
1426bcdc7c4b
151510744791
hexbf9b7b01b

51434205211 has 4 divisors (see below), whose sum is σ = 54459746712. Its totient is φ = 48408663712.

The previous prime is 51434205209. The next prime is 51434205217. The reversal of 51434205211 is 11250243415.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 51434205211 - 21 = 51434205209 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 51434205211.

It is not an unprimeable number, because it can be changed into a prime (51434205217) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1512770725 + ... + 1512770758.

It is an arithmetic number, because the mean of its divisors is an integer number (13614936678).

Almost surely, 251434205211 is an apocalyptic number.

51434205211 is a deficient number, since it is larger than the sum of its proper divisors (3025541501).

51434205211 is a wasteful number, since it uses less digits than its factorization.

51434205211 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3025541500.

The product of its (nonzero) digits is 4800, while the sum is 28.

Adding to 51434205211 its reverse (11250243415), we get a palindrome (62684448626).

The spelling of 51434205211 in words is "fifty-one billion, four hundred thirty-four million, two hundred five thousand, two hundred eleven".

Divisors: 1 17 3025541483 51434205211