51440413001 has 4 divisors (see below), whose sum is σ = 51442161792. Its totient is φ = 51438664212.

The previous prime is 51440412973. The next prime is 51440413039. The reversal of 51440413001 is 10031404415.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 10031404415 = 5 ⋅2006280883.

It is a cyclic number.

It is not a de Polignac number, because 51440413001 - 2²² = 51436218697 is a prime.

It is a super-2 number, since 2×51440413001² (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (51440413081) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 829505 + ... + 889358.

It is an arithmetic number, because the mean of its divisors is an integer number (12860540448).

Almost surely, 2^51440413001 is an apocalyptic number.

It is an amenable number.

51440413001 is a deficient number, since it is larger than the sum of its proper divisors (1748791).

51440413001 is a wasteful number, since it uses less digits than its factorization.

51440413001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1748790.

The product of its (nonzero) digits is 960, while the sum is 23.

Adding to 51440413001 its reverse (10031404415), we get a palindrome (61471817416).

The spelling of 51440413001 in words is "fifty-one billion, four hundred forty million, four hundred thirteen thousand, one".