Base | Representation |
---|---|
bin | 101111111010010111… |
… | …001101110001110001 |
3 | 11220210021220022010112 |
4 | 233322113031301301 |
5 | 1320324411430001 |
6 | 35344501311105 |
7 | 3500566353131 |
oct | 577227156161 |
9 | 156707808115 |
10 | 51445030001 |
11 | 1a8aa418522 |
12 | 9b78a05495 |
13 | 4b0b256671 |
14 | 26c0604ac1 |
15 | 1511681cbb |
hex | bfa5cdc71 |
51445030001 has 4 divisors (see below), whose sum is σ = 51446037504. Its totient is φ = 51444022500.
The previous prime is 51445029973. The next prime is 51445030009. The reversal of 51445030001 is 10003054415.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 51445030001 - 210 = 51445028977 is a prime.
It is a super-2 number, since 2×514450300012 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (51445030009) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 422825 + ... + 530726.
It is an arithmetic number, because the mean of its divisors is an integer number (12861509376).
Almost surely, 251445030001 is an apocalyptic number.
It is an amenable number.
51445030001 is a deficient number, since it is larger than the sum of its proper divisors (1007503).
51445030001 is an equidigital number, since it uses as much as digits as its factorization.
51445030001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1007502.
The product of its (nonzero) digits is 1200, while the sum is 23.
Adding to 51445030001 its reverse (10003054415), we get a palindrome (61448084416).
The spelling of 51445030001 in words is "fifty-one billion, four hundred forty-five million, thirty thousand, one".
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