Base | Representation |
---|---|
bin | 111010011111011111101010… |
… | …1000101110010100100100011 |
3 | 2111110200220121011121210021101 |
4 | 1310332333111011302210203 |
5 | 1014414100100104420003 |
6 | 5022130542410535231 |
7 | 213241354151566123 |
oct | 16476772505624443 |
9 | 2443626534553241 |
10 | 514502002420003 |
11 | 139a3308a365714 |
12 | 49855b27737517 |
13 | 1911143b5793c0 |
14 | 910a05ba36c83 |
15 | 3e735a011e11d |
hex | 1d3efd5172923 |
514502002420003 has 8 divisors (see below), whose sum is σ = 554080218051248. Its totient is φ = 474923949434784.
The previous prime is 514502002420001. The next prime is 514502002420121. The reversal of 514502002420003 is 300024200205415.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 514502002420003 - 21 = 514502002420001 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (514502002420001) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 34051725 + ... + 46781662.
It is an arithmetic number, because the mean of its divisors is an integer number (69260027256406).
Almost surely, 2514502002420003 is an apocalyptic number.
514502002420003 is a deficient number, since it is larger than the sum of its proper divisors (39578215631245).
514502002420003 is a wasteful number, since it uses less digits than its factorization.
514502002420003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 81323013.
The product of its (nonzero) digits is 9600, while the sum is 28.
Adding to 514502002420003 its reverse (300024200205415), we get a palindrome (814526202625418).
The spelling of 514502002420003 in words is "five hundred fourteen trillion, five hundred two billion, two million, four hundred twenty thousand, three".
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