Base | Representation |
---|---|
bin | 1110111111010100011… |
… | …00110110010110011001 |
3 | 1211020101100110100121011 |
4 | 13133222030312112121 |
5 | 31414240232020423 |
6 | 1032333543413521 |
7 | 52131634462444 |
oct | 7375214662631 |
9 | 1736340410534 |
10 | 515030345113 |
11 | 189472226219 |
12 | 839967542a1 |
13 | 3974b05cbcb |
14 | 1acdb4a665b |
15 | d5e543db0d |
hex | 77ea336599 |
515030345113 has 8 divisors (see below), whose sum is σ = 516658016000. Its totient is φ = 513403894080.
The previous prime is 515030345083. The next prime is 515030345119. The reversal of 515030345113 is 311543030515.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 515030345113 - 221 = 515028247961 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (515030345119) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 544513 + ... + 1151761.
It is an arithmetic number, because the mean of its divisors is an integer number (64582252000).
Almost surely, 2515030345113 is an apocalyptic number.
It is an amenable number.
515030345113 is a deficient number, since it is larger than the sum of its proper divisors (1627670887).
515030345113 is a wasteful number, since it uses less digits than its factorization.
515030345113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 609927.
The product of its (nonzero) digits is 13500, while the sum is 31.
Adding to 515030345113 its reverse (311543030515), we get a palindrome (826573375628).
The spelling of 515030345113 in words is "five hundred fifteen billion, thirty million, three hundred forty-five thousand, one hundred thirteen".
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