Base | Representation |
---|---|
bin | 100101011111100110101… |
… | …1101001001111110010011 |
3 | 200020122002021210020112222 |
4 | 1022333031131021332103 |
5 | 1133412033331311321 |
6 | 14543150214211255 |
7 | 1041204636515063 |
oct | 112771535117623 |
9 | 20218067706488 |
10 | 5153112760211 |
11 | 17074718a2509 |
12 | 6b285b053b2b |
13 | 2b4c234b8770 |
14 | 13b5aa6d33a3 |
15 | 8e09e71a3ab |
hex | 4afcd749f93 |
5153112760211 has 4 divisors (see below), whose sum is σ = 5549506049472. Its totient is φ = 4756719470952.
The previous prime is 5153112760199. The next prime is 5153112760241. The reversal of 5153112760211 is 1120672113515.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5153112760211 - 222 = 5153108565907 is a prime.
It is a super-2 number, since 2×51531127602112 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5153112760241) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 198196644611 + ... + 198196644636.
It is an arithmetic number, because the mean of its divisors is an integer number (1387376512368).
Almost surely, 25153112760211 is an apocalyptic number.
5153112760211 is a deficient number, since it is larger than the sum of its proper divisors (396393289261).
5153112760211 is a wasteful number, since it uses less digits than its factorization.
5153112760211 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 396393289260.
The product of its (nonzero) digits is 12600, while the sum is 35.
Adding to 5153112760211 its reverse (1120672113515), we get a palindrome (6273784873726).
The spelling of 5153112760211 in words is "five trillion, one hundred fifty-three billion, one hundred twelve million, seven hundred sixty thousand, two hundred eleven".
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