Base | Representation |
---|---|
bin | 10111011100000110011000… |
… | …00001001101101100110011 |
3 | 20202111110120102010100021201 |
4 | 23232003030001031230303 |
5 | 23223440111242003243 |
6 | 301342312530232031 |
7 | 13566601225541026 |
oct | 1356031401155463 |
9 | 222443512110251 |
10 | 51543030422323 |
11 | 15472304a49680 |
12 | 5945474725617 |
13 | 229b64399562b |
14 | ca29a5ac71bd |
15 | 5e5b44a9404d |
hex | 2ee0cc04db33 |
51543030422323 has 16 divisors (see below), whose sum is σ = 61145424738144. Its totient is φ = 42909069980160.
The previous prime is 51543030422287. The next prime is 51543030422327. The reversal of 51543030422323 is 32322403034515.
It is a cyclic number.
It is not a de Polignac number, because 51543030422323 - 221 = 51543028325171 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (37).
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (51543030422327) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3724738740 + ... + 3724752577.
It is an arithmetic number, because the mean of its divisors is an integer number (3821589046134).
Almost surely, 251543030422323 is an apocalyptic number.
51543030422323 is a deficient number, since it is larger than the sum of its proper divisors (9602394315821).
51543030422323 is a wasteful number, since it uses less digits than its factorization.
51543030422323 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7449491382.
The product of its (nonzero) digits is 259200, while the sum is 37.
Adding to 51543030422323 its reverse (32322403034515), we get a palindrome (83865433456838).
The spelling of 51543030422323 in words is "fifty-one trillion, five hundred forty-three billion, thirty million, four hundred twenty-two thousand, three hundred twenty-three".
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