Base | Representation |
---|---|
bin | 10111011100000110100110… |
… | …01110100001001010000011 |
3 | 20202111110212211200010102111 |
4 | 23232003103032201022003 |
5 | 23223440333221203103 |
6 | 301342332530200151 |
7 | 13566604224446026 |
oct | 1356032316411203 |
9 | 222443784603374 |
10 | 51543151350403 |
11 | 15472367234739 |
12 | 59454a9123057 |
13 | 229b662a55acb |
14 | ca29b7ba51bd |
15 | 5e5b504ce86d |
hex | 2ee0d33a1283 |
51543151350403 has 8 divisors (see below), whose sum is σ = 52135004106000. Its totient is φ = 50951581177728.
The previous prime is 51543151350391. The next prime is 51543151350407. The reversal of 51543151350403 is 30405315134515.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 51543151350403 - 29 = 51543151349891 is a prime.
It is a super-2 number, since 2×515431513504032 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (51543151350407) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 70278826 + ... + 71008447.
It is an arithmetic number, because the mean of its divisors is an integer number (6516875513250).
Almost surely, 251543151350403 is an apocalyptic number.
51543151350403 is a deficient number, since it is larger than the sum of its proper divisors (591852755597).
51543151350403 is a wasteful number, since it uses less digits than its factorization.
51543151350403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 141291461.
The product of its (nonzero) digits is 270000, while the sum is 40.
Adding to 51543151350403 its reverse (30405315134515), we get a palindrome (81948466484918).
The spelling of 51543151350403 in words is "fifty-one trillion, five hundred forty-three billion, one hundred fifty-one million, three hundred fifty thousand, four hundred three".
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