Base | Representation |
---|---|
bin | 111010100110010101100101… |
… | …0011000001010010001011001 |
3 | 2111121000210222112012022000220 |
4 | 1311030223022120022101121 |
5 | 1020030002034123232441 |
6 | 5024130551250350253 |
7 | 213366325454563656 |
oct | 16514531230122131 |
9 | 2447023875168026 |
10 | 515442420524121 |
11 | 13a2659a2914342 |
12 | 4998823b88b389 |
13 | 1917c01c8c783c |
14 | 913d790d44c2d |
15 | 3e8cc90bc0466 |
hex | 1d4caca60a459 |
515442420524121 has 16 divisors (see below), whose sum is σ = 693736193032128. Its totient is φ = 340388988940800.
The previous prime is 515442420524099. The next prime is 515442420524173. The reversal of 515442420524121 is 121425024244515.
It is not a de Polignac number, because 515442420524121 - 213 = 515442420515929 is a prime.
It is not an unprimeable number, because it can be changed into a prime (515442420524021) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 61659220 + ... + 69517941.
It is an arithmetic number, because the mean of its divisors is an integer number (43358512064508).
Almost surely, 2515442420524121 is an apocalyptic number.
It is an amenable number.
515442420524121 is a deficient number, since it is larger than the sum of its proper divisors (178293772508007).
515442420524121 is a wasteful number, since it uses less digits than its factorization.
515442420524121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 131189512.
The product of its (nonzero) digits is 512000, while the sum is 42.
Adding to 515442420524121 its reverse (121425024244515), we get a palindrome (636867444768636).
The spelling of 515442420524121 in words is "five hundred fifteen trillion, four hundred forty-two billion, four hundred twenty million, five hundred twenty-four thousand, one hundred twenty-one".
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