Base | Representation |
---|---|
bin | 1001100110011101… |
… | …00100101001011001 |
3 | 111022012221221102200 |
4 | 10303032210221121 |
5 | 41024013103213 |
6 | 2211245120413 |
7 | 241505615253 |
oct | 46316445131 |
9 | 14265857380 |
10 | 5154425433 |
11 | 22055a2133 |
12 | bba259109 |
13 | 641b49ba1 |
14 | 36c7bccd3 |
15 | 2027ac273 |
hex | 1333a4a59 |
5154425433 has 6 divisors (see below), whose sum is σ = 7445281194. Its totient is φ = 3436283616.
The previous prime is 5154425417. The next prime is 5154425453. The reversal of 5154425433 is 3345244515.
5154425433 is a `hidden beast` number, since 51 + 544 + 25 + 43 + 3 = 666.
It can be written as a sum of positive squares in only one way, i.e., 3257213184 + 1897212249 = 57072^2 + 43557^2 .
It is not a de Polignac number, because 5154425433 - 24 = 5154425417 is a prime.
It is not an unprimeable number, because it can be changed into a prime (5154425453) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 286356960 + ... + 286356977.
It is an arithmetic number, because the mean of its divisors is an integer number (1240880199).
Almost surely, 25154425433 is an apocalyptic number.
It is an amenable number.
5154425433 is a deficient number, since it is larger than the sum of its proper divisors (2290855761).
5154425433 is a wasteful number, since it uses less digits than its factorization.
5154425433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 572713943 (or 572713940 counting only the distinct ones).
The product of its digits is 144000, while the sum is 36.
The square root of 5154425433 is about 71794.3273037640. The cubic root of 5154425433 is about 1727.4020092374.
Adding to 5154425433 its reverse (3345244515), we get a palindrome (8499669948).
The spelling of 5154425433 in words is "five billion, one hundred fifty-four million, four hundred twenty-five thousand, four hundred thirty-three".
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