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51550213441 = 315413073771
BaseRepresentation
bin110000000000101000…
…011101010101000001
311221001121211011200111
4300000220131111001
51321033323312231
635403135551321
73503314404316
oct600050352501
9157047734614
1051550213441
111a95382a391
129ba808b541
134b26c9359c
1426d0584d0d
15151aa0c4b1
hexc00a1d541

51550213441 has 8 divisors (see below), whose sum is σ = 53311501568. Its totient is φ = 49795074000.

The previous prime is 51550213433. The next prime is 51550213493. The reversal of 51550213441 is 14431205515.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 51550213441 - 23 = 51550213433 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (31).

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (51550210441) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1520115 + ... + 1553656.

It is an arithmetic number, because the mean of its divisors is an integer number (6663937696).

Almost surely, 251550213441 is an apocalyptic number.

It is an amenable number.

51550213441 is a deficient number, since it is larger than the sum of its proper divisors (1761288127).

51550213441 is a wasteful number, since it uses less digits than its factorization.

51550213441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3074343.

The product of its (nonzero) digits is 12000, while the sum is 31.

Adding to 51550213441 its reverse (14431205515), we get a palindrome (65981418956).

The spelling of 51550213441 in words is "fifty-one billion, five hundred fifty million, two hundred thirteen thousand, four hundred forty-one".

Divisors: 1 31 541 16771 3073771 95286901 1662910111 51550213441