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51623203423451 = 114693018493041
BaseRepresentation
bin10111011110011011101101…
…01100111100010011011011
320202210010111210202210012212
423233031312230330103123
523231243310034022301
6301443212224025335
713605440051031062
oct1357156654742333
9222703453683185
1051623203423451
11154a3306577aa0
125958b0a46224b
1322a607c8c077a
14ca680d8171d9
155e7c883374bb
hex2ef376b3c4db

51623203423451 has 4 divisors (see below), whose sum is σ = 56316221916504. Its totient is φ = 46930184930400.

The previous prime is 51623203423423. The next prime is 51623203423483. The reversal of 51623203423451 is 15432430232615.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 51623203423451 - 214 = 51623203407067 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 51623203423399 and 51623203423408.

It is not an unprimeable number, because it can be changed into a prime (51623203422451) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2346509246510 + ... + 2346509246531.

It is an arithmetic number, because the mean of its divisors is an integer number (14079055479126).

Almost surely, 251623203423451 is an apocalyptic number.

51623203423451 is a deficient number, since it is larger than the sum of its proper divisors (4693018493053).

51623203423451 is a wasteful number, since it uses less digits than its factorization.

51623203423451 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4693018493052.

The product of its (nonzero) digits is 518400, while the sum is 41.

The spelling of 51623203423451 in words is "fifty-one trillion, six hundred twenty-three billion, two hundred three million, four hundred twenty-three thousand, four hundred fifty-one".

Divisors: 1 11 4693018493041 51623203423451