Base | Representation |
---|---|
bin | 1111000001101111101… |
… | …00010101011000000001 |
3 | 1211100202002202210010210 |
4 | 13200313310111120001 |
5 | 31424422112311231 |
6 | 1033111102144333 |
7 | 52206126121263 |
oct | 7406764253001 |
9 | 1740662683123 |
10 | 516332541441 |
11 | 189a80293632 |
12 | 8409a8820a9 |
13 | 398c7a86792 |
14 | 1adc23d9b33 |
15 | d66e914a46 |
hex | 7837d15601 |
516332541441 has 4 divisors (see below), whose sum is σ = 688443388592. Its totient is φ = 344221694292.
The previous prime is 516332541421. The next prime is 516332541493. The reversal of 516332541441 is 144145233615.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 516332541441 - 215 = 516332508673 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 516332541441.
It is not an unprimeable number, because it can be changed into a prime (516332541401) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 86055423571 + ... + 86055423576.
It is an arithmetic number, because the mean of its divisors is an integer number (172110847148).
Almost surely, 2516332541441 is an apocalyptic number.
It is an amenable number.
516332541441 is a deficient number, since it is larger than the sum of its proper divisors (172110847151).
516332541441 is a wasteful number, since it uses less digits than its factorization.
516332541441 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 172110847150.
The product of its digits is 172800, while the sum is 39.
The spelling of 516332541441 in words is "five hundred sixteen billion, three hundred thirty-two million, five hundred forty-one thousand, four hundred forty-one".
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