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51634363130017 = 71727244551127
BaseRepresentation
bin10111011110110000011111…
…10111110110000010100001
320202211012022112201121200021
423233120033313312002201
523231434133430130032
6301452255435153441
713606313440001533
oct1357301767660241
9222735275647607
1051634363130017
11154a8012977788
12595b1038a5881
1322a713a935135
14ca718b9bb853
155e81dce22097
hex2ef60fdf60a1

51634363130017 has 4 divisors (see below), whose sum is σ = 52361607681216. Its totient is φ = 50907118578820.

The previous prime is 51634363130011. The next prime is 51634363130027. The reversal of 51634363130017 is 71003136343615.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 51634363130017 - 219 = 51634362605729 is a prime.

It is a super-2 number, since 2×516343631300172 (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (51634363130011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 363622275493 + ... + 363622275634.

It is an arithmetic number, because the mean of its divisors is an integer number (13090401920304).

Almost surely, 251634363130017 is an apocalyptic number.

It is an amenable number.

51634363130017 is a deficient number, since it is larger than the sum of its proper divisors (727244551199).

51634363130017 is an equidigital number, since it uses as much as digits as its factorization.

51634363130017 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 727244551198.

The product of its (nonzero) digits is 408240, while the sum is 43.

The spelling of 51634363130017 in words is "fifty-one trillion, six hundred thirty-four billion, three hundred sixty-three million, one hundred thirty thousand, seventeen".

Divisors: 1 71 727244551127 51634363130017