Base | Representation |
---|---|
bin | 111010101110000000100110… |
… | …1011011110111010110111001 |
3 | 2111201202121202001120201021212 |
4 | 1311130001031123313112321 |
5 | 1020144241110343014131 |
6 | 5030255221031412505 |
7 | 213535445222016545 |
oct | 16534011533672671 |
9 | 2451677661521255 |
10 | 516496886298041 |
11 | 13a6321102a6330 |
12 | 49b18682224135 |
13 | 192275a7bb516c |
14 | 9178822c38a25 |
15 | 3eaa408da8a2b |
hex | 1d5c04d6f75b9 |
516496886298041 has 4 divisors (see below), whose sum is σ = 563451148688784. Its totient is φ = 469542623907300.
The previous prime is 516496886298017. The next prime is 516496886298047. The reversal of 516496886298041 is 140892688694615.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-516496886298041 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (516496886298047) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23477131195355 + ... + 23477131195376.
It is an arithmetic number, because the mean of its divisors is an integer number (140862787172196).
Almost surely, 2516496886298041 is an apocalyptic number.
It is an amenable number.
516496886298041 is a deficient number, since it is larger than the sum of its proper divisors (46954262390743).
516496886298041 is a wasteful number, since it uses less digits than its factorization.
516496886298041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 46954262390742.
The product of its (nonzero) digits is 1433272320, while the sum is 77.
The spelling of 516496886298041 in words is "five hundred sixteen trillion, four hundred ninety-six billion, eight hundred eighty-six million, two hundred ninety-eight thousand, forty-one".
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