Base | Representation |
---|---|
bin | 111010101110011001111101… |
… | …0001001100000111001111001 |
3 | 2111201221211020212212210221211 |
4 | 1311130303322021200321321 |
5 | 1020201134102312202101 |
6 | 5030340222503003121 |
7 | 213542413224035053 |
oct | 16534637211407171 |
9 | 2451854225783854 |
10 | 516551323553401 |
11 | 13a653205753a74 |
12 | 49b271351394a1 |
13 | 1922c772030376 |
14 | 917b3089c08d3 |
15 | 3eaba43095c51 |
hex | 1d5ccfa260e79 |
516551323553401 has 4 divisors (see below), whose sum is σ = 517207678476112. Its totient is φ = 515894968630692.
The previous prime is 516551323553233. The next prime is 516551323553429. The reversal of 516551323553401 is 104355323155615.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 516551323553401 - 29 = 516551323552889 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (516551323553431) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 328177460175 + ... + 328177461748.
It is an arithmetic number, because the mean of its divisors is an integer number (129301919619028).
Almost surely, 2516551323553401 is an apocalyptic number.
It is an amenable number.
516551323553401 is a deficient number, since it is larger than the sum of its proper divisors (656354922711).
516551323553401 is an equidigital number, since it uses as much as digits as its factorization.
516551323553401 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 656354922710.
The product of its (nonzero) digits is 4050000, while the sum is 49.
The spelling of 516551323553401 in words is "five hundred sixteen trillion, five hundred fifty-one billion, three hundred twenty-three million, five hundred fifty-three thousand, four hundred one".
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